(PHP 4 >= 4.0.4, PHP 5, PHP 7, PHP 8)

ctype_xdigit Verifica se os caracteres representam um dígito hexadecimal


ctype_xdigit(string $text): bool

Verifica se todos os caracteres na string fornecida, text, são 'dígitos' hexadecimal.



A string a ser testada.

Valor Retornado

Retorna true se todos caracteres em text é um 'dígito' hexadecimal, que é um dígito ou um caractere de [A-Fa-f], false caso contrário.


Exemplo #1 Um exemplo da ctype_xdigit()

= array('AB10BC99', 'AR1012', 'ab12bc99');
foreach (
$strings as $testcase) {
if (
ctype_xdigit($testcase)) {
"The string $testcase consists of all hexadecimal digits.\n";
} else {
"The string $testcase does not consist of all hexadecimal digits.\n";

O exemplo acima produzirá:

The string AB10BC99 consists of all hexadecimal digits.
The string AR1012 does not consist of all hexadecimal digits.
The string ab12bc99 consists of all hexadecimal digits.

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User Contributed Notes 2 notes

tom at hgmail dot com
17 years ago
This function shows its usefulness on a web site where a user is asked to entered a hexidecimal color code for a color. To prevent breaking W3C standard and having them enter in "neon-green" or the wrong type of code like 355511235.

In conjunction with strlen()  you could create a function like this:

function check_valid_colorhex($colorCode) {
    // If user accidentally passed along the # sign, strip it off
    $colorCode = ltrim($colorCode, '#');

    if (
          ctype_xdigit($colorCode) &&
          (strlen($colorCode) == 6 || strlen($colorCode) == 3))
               return true;

    else return false;
3 months ago
this can be used with great results if you wanna check for something like

"Tobias2" whether there is a number at the end of the string. (F.e. courselist with coursenames etc.)

Just substring the last char and put it in the function.
We should be glad about every possibility to cut out these damn regexes from our code. NEVER USE REGEX
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