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ArrayObject::exchangeArray

(PHP 5 >= 5.1.0, PHP 7, PHP 8)

ArrayObject::exchangeArray配列を別の配列と交換する

説明

public ArrayObject::exchangeArray(array|object $array): array

現在の配列を、別の配列あるいはオブジェクトと交換します。

パラメータ

array

現在の配列と交換する配列あるいはオブジェクト。

返り値

元の配列を返します。

例1 ArrayObject::exchangeArray() の例

<?php
// フルーツの配列
$fruits = array("lemons" => 1"oranges" => 4"bananas" => 5"apples" => 10);
// ヨーロッパの都市の配列
$locations = array('Amsterdam''Paris''London');

$fruitsArrayObject = new ArrayObject($fruits);

// フルーツを都市と交換します
$old $fruitsArrayObject->exchangeArray($locations);
print_r($old);
print_r($fruitsArrayObject);

?>

上の例の出力は以下となります。

Array
(
    [lemons] => 1
    [oranges] => 4
    [bananas] => 5
    [apples] => 10
)
ArrayObject Object
(
    [0] => Amsterdam
    [1] => Paris
    [2] => London
)

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User Contributed Notes 3 notes

up
3
Corentin Larose
7 years ago
It's worth notting that ArrayObject::exchangeArray() doesn't call ArrayObject::offsetSet() internally for each offset/property of the array/object provided in argument.

It's also worth noting the let's say "unexpected" behavior of get/set:

<?php
class MyArrayObject extends ArrayObject
{
    public function
offsetSet($name, $value)
    {
       
parent::offsetSet($name . '_control', $value);
       
parent::offsetSet($name, $value);
    }
}

$test = new MyArrayObject();
$test->setFlags(\ArrayObject::ARRAY_AS_PROPS);
$test['my_value_1'] = 1;
$test['my_value_1'] = $test['my_value_1'] + 1;
$test['my_value_1'] += 1;
$test['my_value_1'] ++;
++
$test['my_value_1'];

$test->my_value_2 = 1;
$test->my_value_2 = $test->my_value_2 + 1;
$test->my_value_2 += 1;
$test->my_value_2 ++;
++
$test->my_value_2;

print_r($test);

// Prints out:
MyArrayObject Object
(
    [
storage:ArrayObject:private] => Array
        (
            [
my_value_1_control] => 3
           
[my_value_1] => 5
           
[my_value_2_control] => 2
           
[my_value_2] => 5
       
)
)
?>
up
5
Dmitri Snytkine
11 years ago
It seems that input array is always passed by reference.
For example if you have an existing array
$array with some values
then you have an arrayobject $o
and then you do this:
$o->exchangeArray($array);
$o->offsetSet('somekey', 'some value');

Now if you check your $array array, it will have
a key 'somekey' with value of 'some value'

I totally did not expect that, I am sure it was a mistake to pass array by reference by default.
up
0
ievgen dot varava at spryker dot com
6 months ago
Looks like PHP8 brings undocumented change to this method signature. Example:

<?php
interface intA {
    public function
exchangeArray($param);
}

class
classB extends ArrayObject implements intA {}
?>

PHP 7.4.13: no errors

PHP 8.0.0: Fatal error:  Declaration of ArrayObject::exchangeArray(object|array $array) must be compatible with intA::exchangeArray($param)
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