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mysqli::stmt_init

mysqli_stmt_init

(PHP 5, PHP 7, PHP 8)

mysqli::stmt_init -- mysqli_stmt_initステートメントを初期化し、mysqli_stmt_prepare で使用するオブジェクトを返す

説明

オブジェクト指向型

public mysqli::stmt_init(): mysqli_stmt|false

手続き型

mysqli_stmt_init(mysqli $mysql): mysqli_stmt|false

mysqli_stmt_prepare() で使用可能な ステートメントオブジェクトを割り当て、初期化します。

注意:

mysqli_stmt_prepare() がコールされるまで、 これ以降のあらゆる mysqli_stmt 関数のコールは失敗します。

パラメータ

link

手続き型のみ: mysqli_connect() あるいは mysqli_init() が返す mysqliオブジェクト。

戻り値

オブジェクトを返します。

参考

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User Contributed Notes 2 notes

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17
Jeff C
8 years ago
stmt_init() seems to clear previous (possibly erroneous) results on the DB connection, which means you don't necessarily need to use it but it could make the code more robust.

In a PHPUnit test, I had a sequence of prepared queries on the same connection. One of them fetched a row from a SELECT but didn't keep fetching until it drained the connection, so it left some stale results. When the next query did this:

<?php
$db
= $this->getConnection()->getDbConnection();
$preparedQuery = $db->prepare ($query);
?>

the prepare() call generated an error: "Could not prepare query: Commands out of sync; you can't run this command now." Changing to this:

<?php
$db
= $this->getConnection()->getDbConnection();
$preparedQuery = $db->stmt_init();
$preparedQuery->prepare ($query);
?>

resolved the problem.
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5
mamdo7 at hotmail dot com
10 years ago
you can use $stmt = $mysqli->prepare(); directly without stmt-init() . i think there is no need for stmt-init .
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