ConFoo 2025

ReflectionClass::hasMethod

(PHP 5 >= 5.1.2, PHP 7, PHP 8)

ReflectionClass::hasMethodメソッドが定義されているかどうかを調べる

説明

public ReflectionClass::hasMethod(string $name): bool

そのクラスで特定のメソッドが定義されているかどうかを調べます。

パラメータ

name

調べたいメソッドの名前。

戻り値

メソッドが定義されている場合に true、それ以外の場合に false を返します。

例1 ReflectionClass::hasMethod() の例

<?php
Class C {
public function
publicFoo() {
return
true;
}

protected function
protectedFoo() {
return
true;
}

private function
privateFoo() {
return
true;
}

static function
staticFoo() {
return
true;
}
}

$rc = new ReflectionClass("C");

var_dump($rc->hasMethod('publicFoo'));

var_dump($rc->hasMethod('protectedFoo'));

var_dump($rc->hasMethod('privateFoo'));

var_dump($rc->hasMethod('staticFoo'));

// C には bar メソッドがありません
var_dump($rc->hasMethod('bar'));

// メソッド名は大文字小文字を区別しません
var_dump($rc->hasMethod('PUBLICfOO'));
?>

上の例の出力は以下となります。

bool(true)
bool(true)
bool(true)
bool(true)
bool(false)
bool(true)

参考

add a note

User Contributed Notes 6 notes

up
4
phoenix at todofixthis dot com
14 years ago
Parent methods (regardless of visibility) are also available to a ReflectionObject. E.g.,

<?php
class ParentObject {
public function
parentPublic( ) {
}

private function
parentPrivate( ) {
}
}

class
ChildObject extends ParentObject {
}

$Instance = new ChildObject();
$Reflector = new ReflectionObject($Instance);

var_dump($Reflector->hasMethod('parentPublic')); // true
var_dump($Reflector->hasMethod('parentPrivate')); // true
?>
up
1
dn dot permyakov at gmail dot com
5 years ago
Trait methods can be seen by both actual and alias names

<?php

trait Sauce
{
public function
getSpicy()
{
return
'Cayenne';
}
}

class
Sandwich
{
use
Sauce {
Sauce::getSpicy as getSweet;
}
}

$class = new \ReflectionClass('Sandwich');
var_dump($class->hasMethod('getSweet'));
var_dump($class->hasMethod('getSpicy'));
?>
bool(true)
bool(true)
up
0
flancer64 at gmail dot com
8 years ago
Annotated methods that are implemented using PHP magic methods are not recognized by "hasMethod".

<?php
/**
* @method void annotatedMethod()
*/
class SomeClass
{
public function
__call($name, $arguments)
{
echo
"this is magic method: $name.\n";
}

public function
codedMethod()
{
echo
"this is coded method.\n";
}
}

$obj = new \SomeClass();
$obj->codedMethod();
$obj->annotatedMethod();

$ref = new ReflectionClass(\SomeClass::class);
echo
"SomeClass has 'codedMethod': " . json_encode($ref->hasMethod('codedMethod')) . ".\n";
echo
"SomeClass has 'annotatedMethod': " . json_encode($ref->hasMethod('annotatedMethod')) . ".\n";
?>

Output:

this is coded method.
this is magic method: annotatedMethod.
SomeClass has 'codedMethod': true.
SomeClass has 'annotatedMethod': false.
up
0
hanguofeng at gmail dot com
14 years ago
note that even if private method will also be 'has'.
up
-1
Xorifelse
7 years ago
It might be interesting to know that this is the only method to determine if a trait has a specific method:

trait a{
function __wakeup(){}
}

class b{}

class c{
use a;
}

var_dump((new ReflectionClass('a'))->hasMethod('__wakeup')); // true
var_dump((new ReflectionClass('b'))->hasMethod('__wakeup')); // false
var_dump((new ReflectionClass('c'))->hasMethod('__wakeup')); // true
up
-4
michaelgranados at gmail dot com
12 years ago
A way to check if you can call an method over a class:

<?php
function is_public_method(
/* string */$className,
/* string */$method
){
$classInstance = new ReflectionClass($className);
if (
$classInstance->hasMethod($method)) {
return
false;
}
$methodInstance = $instance->getMethod($method);
return
$methodInstance->isPublic();
}
?>
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