mysql_result

(PHP 4, PHP 5)

mysql_result取得结果数据

警告

本扩展自 PHP 5.5.0 起已废弃,并在自 PHP 7.0.0 开始被移除。应使用 MySQLiPDO_MySQL 扩展来替换之。参见 MySQL:选择 API 指南来获取更多信息。用以替代本函数的有:

说明

mysql_result(resource $result, int $row, mixed $field = 0): string

Retrieves the contents of one cell from a MySQL result set.

When working on large result sets, you should consider using one of the functions that fetch an entire row (specified below). As these functions return the contents of multiple cells in one function call, they're MUCH quicker than mysql_result(). Also, note that specifying a numeric offset for the field argument is much quicker than specifying a fieldname or tablename.fieldname argument.

参数

result

resource 型的结果集。此结果集来自对 mysql_query() 的调用。

row

The row number from the result that's being retrieved. Row numbers start at 0.

field

The name or offset of the field being retrieved.

It can be the field's offset, the field's name, or the field's table dot field name (tablename.fieldname). If the column name has been aliased ('select foo as bar from...'), use the alias instead of the column name. If undefined, the first field is retrieved.

返回值

The contents of one cell from a MySQL result set on success, or false on failure.

示例

示例 #1 mysql_result() 示例

<?php
$link
= mysql_connect('localhost', 'mysql_user', 'mysql_password');
if (!
$link) {
die(
'Could not connect: ' . mysql_error());
}
if (!
mysql_select_db('database_name')) {
die(
'Could not select database: ' . mysql_error());
}
$result = mysql_query('SELECT name FROM work.employee');
if (!
$result) {
die(
'Could not query:' . mysql_error());
}
echo
mysql_result($result, 2); // outputs third employee's name

mysql_close($link);
?>

注释

注意:

Calls to mysql_result() should not be mixed with calls to other functions that deal with the result set.

参见

添加备注

用户贡献的备注 4 notes

up
18
freedman at FreeFormIT dot com
9 years ago
here's a rough replacement using mysqli:

if (!function_exists('mysql_result')) {
function mysql_result($result, $number, $field=0) {
mysqli_data_seek($result, $number);
$row = mysqli_fetch_array($result);
return $row[$field];
}
}
up
1
bob dot schuon at loungelizard dot com
5 years ago
This function accounts for the ability of the original function to accept "table_name.field_name" entries as well as just the field name:

function mysqli_result($res, $row, $field=0) {
$result->data_seek($row);
$data = $result->fetch_array();
$field_name = $field;
if ( is_string($field) ) {
$fields_array = explode(".", $field);
$array_len = count($fields_array);
if ($array_len > 1) {
$field_name = $fields_array[array_len - 1];
} else {
$field_name = $fields_array[0];
}
}

return $data[$field_name];
}
up
1
mark at pnod dot co dot uk
1 year ago
To replace a row count e.g.

$querystring = "SELECT COUNT(*) FROM table WHERE column1 = 'EXAMPLE'";
$total_records = mysql_result(mysql_query($querystring,$connection),0);

use mysqli_fetch_row :

$querystring = "SELECT COUNT(*) FROM table WHERE column1 = 'EXAMPLE'";
$rowcount = mysqli_fetch_row(mysqli_query($connection,$querystring));
$total_records = $rowcount[0];
up
-3
v dot teemu at gmail dot com
8 years ago
I was also looking for mysqli replacement for getting first row, when query is known to return just 1 value. It seems this is simple:

echo(mysql_result($result, 0));

becomes

echo($result->fetch_row()[0]);

alternatively

if ($row = $result->fetch_row()) {
echo($row[0]);
}
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