PHP 8.3.4 Released!

array_intersect_assoc

(PHP 4 >= 4.3.0, PHP 5, PHP 7, PHP 8)

array_intersect_assoc带索引检查计算数组的交集

说明

array_intersect_assoc(array $array, array ...$arrays): array

array_intersect_assoc() 返回一个数组,该数组包含了所有在 array 和其它参数数组中同时存在的值。注意和 array_intersect() 不同的是,键名也用于比较。

参数

array

要检查的数组,作为主值。

arrays

要被对比的数组。

返回值

返回一个关联数组,该数组包含了所有在 array 和其它参数数组中同时存在的值。

更新日志

版本 说明
8.0.0 现在可以仅使用一个参数调用此函数。以前,至少需要两个参数。

示例

示例 #1 array_intersect_assoc() 例子

<?php
$array1
= array("a" => "green", "b" => "brown", "c" => "blue", "red");
$array2 = array("a" => "green", "b" => "yellow", "blue", "red");
$result_array = array_intersect_assoc($array1, $array2);
print_r($result_array);
?>

以上示例会输出:

Array
(
    [a] => green
)

上面例子中可以看到,只有键值对 "a" => "green" 在两个数组中都存在,从而被返回。 值 "red" 没有被返回,是因为在 $array1 中它的键名是 0 而在 $array2 中 "red" 的键名是 1,键 "b" 没有返回的原因是,它的值和其他数组不同。

仅在 (string) $elem1 === (string) $elem2 时, key => value 才被认为是相等的。 也就是说使用了严格的类型检查,字符串的表达形式必须相同。

参见

add a note

User Contributed Notes 4 notes

up
6
Whitend
11 years ago
One of the ways to get intersection of two arrays is as follows:

<?php
function arrayIntersect( $primary_array, $secondary_array ) {

if ( !
is_array( $primary_array ) || !is_array( $secondary_array ) ) {
return
false;
}

if ( !empty(
$primary_array ) ) {

foreach(
$primary_array as $key => $value ) {

if ( !isset(
$secondary_array[$key] ) ) {
unset(
$primary_array[$key] );
} else {
if (
serialize( $secondary_array[$key] ) != serialize( $value ) ) {
unset(
$primary_array[$key] );
}
}

}

return
$primary_array;

} else {
return array();
}

}
?>

It would pay attention to both keys and values even if values would be arrays as well. One important note is that if value of $primary_array is yet another array, its order of key & value pairs becomes important for matching.
up
4
vandor at progressive dot hu
19 years ago
# ket tomb kulcs alapu metszetet szamitja ki, az erteken is ellenorzest vegez
#
# calculating (key base) intersection of arrays (value are checked)
# use: $result_array = array_intersect_assoc($a1, $a2, $a3,..);
#
##
# original code by [jochem at iamjochem dawt com] : array_diff_keys()

<?php
function array_intersect_assoc() {

$args = func_get_args();
$res = $args[0];

for (
$i=1;$i<count($args);$i++) {
if (!
is_array($args[$i])) {continue;}

foreach (
$res as $key => $data) {
if ( (!
array_key_exists($key, $args[$i])) || ( (isset($args[$i][$key])) && ($args[$i][$key] !== $res[$key]) ) ) {
unset(
$res[$key]);
}
}
}

return
$res;
}

?>

<?php
$array1
= array("a"=>"green", "b"=>"brown", "c"=>"blue", "red");
$array2 = array("a"=>"green", "b"=>"yellow", "c"=>"yellow", "red");
$a = array('a'=>'green', 'b'=>'brown', 'c'=>'yellow');
$b = array('a'=>'green', 'b'=>'brown', 'c'=>'yellow', 'e'=>'yellow');

$result_array = array_intersect_assoc($a, $b, $array1, $array2);
?>

$args array will look like:

(
0 =>
(
a => green
b => brown
c => yellow
)

1 =>
(
a => green
b => brown
c => yellow
e => yellow
)

2 =>
(
a => green
b => brown
c => blue
0 => red
)

3 =>
(
a => green
b => yellow
c => yellow
0 => red
)

)

$result_array will look like:

(
a => green
)
up
-6
Jim Yaghi
6 years ago
Remember, null values will be interpreted as, "key does not exist." eg,

$a = ['apples' => 1, 'oranges' => 2, 'turtles' => null, 'bananas'=>4];
$b = ['apples'=>10, 'turtles' => 11, 'eggs'=>12];
$c = array_intersect_assoc($b,$a);

You might have expected $c to contain:

['oranges' => 10, 'turtles' => 11]

In fact, 'turtles' has a null value in the $a array, therefore the $c array contains only:

['oranges' => 10]

Something to keep in mind if using array_intersect_assoc to filter valid entries, eg in a mySQL insertion pre-processing or nerdy API that doesn't like extra params.
up
-7
StR: str at strgt dot cjb dot net
18 years ago
To find the keys that are in 2 arrays, without caring of the values:

This is a function i needed, and it also returns the values of the first array

<?php
function array_key_intersect(&$a, &$b) {
$array = array();
while (list(
$key,$value) = each($a)) {
if (isset(
$b[$key]))
$array[$key] = $value;
}
return
$array;
}
?>
To Top