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mysqli::query

mysqli_query

(PHP 5, PHP 7, PHP 8)

mysqli::query -- mysqli_queryFührt eine Abfrage in einer Datenbank durch

Beschreibung

Objektorientierter Stil

public mysqli::query(string $query, int $result_mode = MYSQLI_STORE_RESULT): mysqli_result|bool

Prozeduraler Stil

mysqli_query(mysqli $mysql, string $query, int $result_mode = MYSQLI_STORE_RESULT): mysqli_result|bool

Führt in einer Datenbank die Abfrage query durch.

Bei Nicht-DML-Abfragen (nicht INSERT, UPDATE oder DELETE) ist diese Funktion vergleichbar mit dem Aufruf von mysqli_real_query(), gefolgt entweder von mysqli_use_result() oder mysqli_store_result().

Hinweis:

Wenn eine Anweisung an mysqli_query() übergeben wird, die größer ist als die vom Server maximal erlaubte Paketgröße (max_allowed_packet), hängen die zurückgegebenen Fehlercodes davon ab, ob der MySQL Native Driver (mysqlnd) oder die MySQL Client Library (libmysqlclient) verwendet wird. Die Funktion verhält sich wie folgt:

  • mysqlnd gibt unter Linux den Fehlercode 1153 zurück. Diese Fehlermeldung bedeutet got a packet bigger than max_allowed_packet bytes.

  • mysqlnd gibt unter Windows den Fehlercode 2006 zurück. Diese Fehlermeldung bedeutet server has gone away.

  • libmysqlclient gibt auf allen Plattformen den Fehlercode 2006 zurück. Diese Fehlermeldung bedeutet server has gone away.

Parameter-Liste

mysql

Nur bei prozeduralem Aufruf: Ein von mysqli_connect() oder mysqli_init() zurückgegebenes mysqli-Objekt.

query

Die Zeichenkette für die Abfrage

Warnung

Sicherheitswarnung: SQL-Injection

Wenn die Abfrage irgendwelche Eingabevariablen enthält, sollten stattdessen parametrisierte Prepared Statements verwendet werden. Alternativ dazu müssen die Daten korrekt formatiert sein und alle Strings müssen mit der Funktion mysqli_real_escape_string() maskiert werden.

result_mode

Der Ergebnismodus kann eine von 3 Konstanten sein, die bestimmen, wie das Ergebnis vom MySQL-Server zurückgegeben werden soll.

MYSQLI_STORE_RESULT (Standard) - gibt ein mysqli_result-Objekt mit gepufferter Ergebnismenge zurück.

MYSQLI_USE_RESULT - gibt ein mysqli_result-Objekt mit ungepufferter Ergebnismenge zurück. Solange es noch Datensätze gibt, die darauf warten, abgerufen zu werden, ist die Verbindung belegt und alle nachfolgenden Aufrufe geben den Fehler Commands out of sync zurück. Um den Fehler zu vermeiden, müssen alle Datensätze vom Server abgeholt werden oder die Ergebnismenge muss durch den Aufruf von mysqli_free_result() verworfen werden.

MYSQLI_ASYNC (verfügbar mit mysqlnd) - die Abfrage wird asynchron ausgeführt und die Ergebnismenge wird nicht sofort zurückgegeben. Um die Ergebnisse solcher Abfragen zu erhalten, wird dann die Funktion mysqli_poll() benutzt. Dies wird in Kombination mit einer der Konstanten MYSQLI_STORE_RESULT oder MYSQLI_USE_RESULT verwendet.

Rückgabewerte

Gibt bei einem Fehler false zurück. Bei erfolgreichen Abfragen, die eine Ergebnismenge erzeugen, also z. B. SELECT, SHOW, DESCRIBE oder EXPLAIN, gibt mysqli_query() ein mysqli_result-Objekt zurück. Bei anderen erfolgreichen Abfragen gibt mysqli_query() true zurück.

Beispiele

Beispiel #1 mysqli::query()-Beispiel

Objektorientierter Stil

<?php

mysqli_report
(MYSQLI_REPORT_ERROR MYSQLI_REPORT_STRICT);
$mysqli = new mysqli("localhost""my_user""my_password""world");

/* Erstellen einer Tabelle gibt keine Ergebnismenge zurück */
$mysqli->query("CREATE TEMPORARY TABLE myCity LIKE City");
printf("Tabelle myCity erfolgreich erstellt.\n");

/* Select-Abfragen geben eine Ergebnismenge zurück */
$result $mysqli->query("SELECT Name FROM City LIMIT 10");
printf("Select gab %d Zeilen zurück.\n"$result->num_rows);

/* Um große Datenmengen abzurufen, verwenden wir MYSQLI_USE_RESULT */
$result $mysqli->query("SELECT * FROM City"MYSQLI_USE_RESULT);

/* Hinweis: Solange nicht alle Datensätze vollständig abgerufen wurden oder
  die Ergebnismenge geschlossen wurde, können keine Funktionen ausgeführt
  werden, die mit dem Server interagieren. Alle Aufrufe werden einen
  'out of sync'-Fehler zurückgeben */
$mysqli->query("SET @a:='this will not work'");

Prozeduraler Stil

<?php

mysqli_report
(MYSQLI_REPORT_ERROR MYSQLI_REPORT_STRICT);
$link mysqli_connect("localhost""my_user""my_password""world");

/* Erstellen einer Tabelle gibt keine Ergebnismenge zurück */
mysqli_query($link"CREATE TEMPORARY TABLE myCity LIKE City");
printf("Tabelle myCity erfolgreich erstellt.\n");

/* Select-Abfragen geben eine Ergebnismenge zurück */
$result mysqli_query($link"SELECT Name FROM City LIMIT 10");
printf("Select gab %d Zeilen zurück.\n"mysqli_num_rows($result));

/* Um große Datenmengen abzurufen, verwenden wir MYSQLI_USE_RESULT */
$result mysqli_query($link"SELECT * FROM City"MYSQLI_USE_RESULT);

/* Hinweis: Solange nicht alle Datensätze vollständig abgerufen wurden oder
  die Ergebnismenge geschlossen wurde, können keine Funktionen ausgeführt
  werden, die mit dem Server interagieren. Alle Aufrufe werden einen
  'out of sync'-Fehler zurückgeben */
mysqli_query($link"SET @a:='this will not work'");

Oben gezeigte Beispiele erzeugen eine ähnliche Ausgabe wie:

Tabelle myCity erfolgreich erstellt.
Select gab 10 Zeilen zurück.

Fatal error: Uncaught mysqli_sql_exception: Commands out of sync; you can't run this command now in...

Siehe auch

add a note

User Contributed Notes 21 notes

up
45
NUNTIUS
14 years ago
This may or may not be obvious to people but perhaps it will help someone.

When running joins in SQL you may encounter a problem if you are trying to pull two columns with the same name. mysqli returns the last in the query when called by name. So to get what you need you can use an alias.

Below I am trying to join a user id with a user role. in the first table (tbl_usr), role is a number and in the second is a  text name (tbl_memrole is a lookup table). If I call them both as role I get the text as it is the last "role" in the query. If I use an alias then I get both as desired as shown below.

<?php
$sql
= "SELECT a.uid, a.role AS roleid, b.role,
            FROM tbl_usr a
            INNER JOIN tbl_memrole b
            ON a.role = b.id
            "
;

    if (
$result = $mysqli->query($sql)) {
        while(
$obj = $result->fetch_object()){
           
$line.=$obj->uid;
           
$line.=$obj->role;
           
$line.=$obj->roleid;
        }
    }
   
$result->close();
    unset(
$obj);
    unset(
$sql);
    unset(
$query);
   
?>
In this situation I guess I could have just renamed the role column in the first table roleid and that would have taken care of it, but it was a learning experience.
up
3
xa at sagexa dot com
2 months ago
"In PHP 8.1, the default error handling behavior of the MySQLi extension has changed from silencing errors to throw an Exception on errors. "
This is true even for the procedural use of mysqli, i.e. mysqli_query.
Hence, using if(!mysqli_query($c, $sql)) [...] is pointless.
To disable Exception throwing : mysqli_report(MYSQLI_REPORT_OFF);
up
37
theyranos at gmail dot com
11 years ago
The cryptic "Couldn't fetch mysqli" error message can mean any number of things, including:

1. You're trying to use a database object that you've already closed (as noted by ceo at l-i-e dot com). Reopen your database connection, or find the call to <?php mysqli_close($db); ?> or <?php $db->close(); ?> and remove it.
2. Your MySQLi object has been serialized and unserialized for some reason. Define a wakeup function to re-create your database connection. http://php.net/__wakeup
3. Something besides you closed your mysqli connection (in particular, see http://bugs.php.net/bug.php?id=33772)
4. You mixed OOP and functional calls to the database object. (So, you have <?php $db->query() ?> in the same program as <?php mysqli_query($db) ?>).
up
32
petrus.jvr
11 years ago
When calling multiple stored procedures, you can run into the following error: "Commands out of sync; you can't run this command now".
This can happen even when using the close() function on the result object between calls.
To fix the problem, remember to call the next_result() function on the mysqli object after each stored procedure call. See example below:

<?php
// New Connection
$db = new mysqli('localhost','user','pass','database');

// Check for errors
if(mysqli_connect_errno()){
echo
mysqli_connect_error();
}

// 1st Query
$result = $db->query("call getUsers()");
if(
$result){
    
// Cycle through results
   
while ($row = $result->fetch_object()){
       
$user_arr[] = $row;
    }
   
// Free result set
   
$result->close();
   
$db->next_result();
}

// 2nd Query
$result = $db->query("call getGroups()");
if(
$result){
    
// Cycle through results
   
while ($row = $result->fetch_object()){
       
$group_arr[] = $row;
    }
    
// Free result set
    
$result->close();
    
$db->next_result();
}
else echo(
$db->error);

// Close connection
$db->close();
?>
up
15
Anonymous
4 years ago
Here is an example of a clean query into a html table

<table>
   <tr>
     <th>First Name</th>
     <th>Last Name</th>
     <th>City</th>
   </tr>
   <?php while ($row = $myquery->fetch_assoc()) { ?>
   <tr>
     <td><?php echo $row["firstname"]; ?></td>
     <td><?php echo $row["lastname"]; ?></td>
     <td><?php echo $row["city"];?></td>
   </tr>
   <?php } ?>
</table>
up
4
Beeners
16 years ago
Stored Procedures.

Use mysqli_query to call a stored procedure that returns a result set.

Here is a short example:

<?php
$mysqli
= new mysqli(DBURI,DBUSER,DBPASS,DBNAME);
if (
mysqli_connect_errno())
{
 
printf("Connection failed: %s\n", mysqli_connect_error());
  exit();
}

$SQL = "CALL my_procedure($something)";
if ( (
$result = $mysqli->query($SQL))===false )
{
 
printf("Invalid query: %s\nWhole query: %s\n", $mysqli->error, $SQL);
  exit();
}

while (
$myrow = $result->fetch_array(MYSQLI_ASSOC))
{
 
$aValue[]=$myrow["a"];
 
$bValue[]=$myrow["b"];
}
$result->close();
$mysqli->close();
?>
I hope this saves someone some time.
up
3
registrations at jdfoxmicro dot com
12 years ago
I like to save the query itself in a log file, so that I don't have to worry about whether the site is live.

For example, I might have a global function:

<?php
function UpdateLog ( $string , $logfile )  {
  
$fh = fopen ( $logfile , 'a' );
  
$fwrite ( $fh , strftime ('%F %T %z')." ".$string."\n";
  
fclose ( $fh );
}
?>

Then in my mysql function error trapper, something like this:

<?php
   $error_msg
= "Database error in [page].php / ";
  
$error_msg .= mysqli_error ( $link )." / ";
  
$error_msg .= $query;
  
UpdateLog ( $error_msg , DB_ERROR_LOG_FILE );
?>

I also include the remote IP, user agent, etc., but I left it out of these code samples.  And have it e-mail me when an error is caught, too.

Jeff
up
-3
ceo at l-i-e dot com
14 years ago
Translation:
"Couldn't fetch mysqli"

You closed your connection and are trying to use it again.

It has taken me DAYS to figure out what this obscure error message means...
up
-9
jcwebb at dicoe dot com
15 years ago
When building apps, i like to see the whole statement when if fails.
<?php
$q
="SELECT somecolumn FROM sometable"; //some instruction
$r=mysqli_query($DBlink,$q) or die(mysqli_error($DBlink)." Q=".$q);
?>
If theres an error (like my numerous typing mistakes) this shows the entire instruction.
Good for development (not so good on production servers - simply find and replace when finished: $r=mysqli_query($DBlink,$q); )

Hope it helps. Jon
up
-10
info at ff dot net
16 years ago
Calling Stored Procedures

Beeners' note/example will not work. Use mysqli_multi_query() to call a Stored Procedure. SP's have a second result-set which contains the status: 'OK' or 'ERR'. Using mysqli_query will not work, as there are multiple results.

<?php
$sQuery
="CALL SomeSP('params')";
if(!
mysqli_multi_query($sqlLink,$sQuery)) {
 
// your error handler
}
$sqlResult=mysqli_store_result($sqlLink);

if(
mysqli_more_results($this->sqlLink))//Catch 'OK'/'ERR'
 
while(mysqli_next_result($this->sqlLink));
?>

You will have to rewrite/expand this a bit for more usability of course, but it's just an example.
up
-14
joseph_robert_martinez at yahoo dot com
8 years ago
For those using with replication enabled on their servers,  add a mysqli_select_db() statement before any data modification queries.  MySQL replication does not handle statements with db.table the same and will not replicate to the slaves if a scheme is not selected before.

Found out after days of resetting master and slaves on another site http://www.linuxquestions.org/questions/linux-server-73/mysql-5-1-not-replicating-properly-with-slave-823296/
up
-15
Igor
14 years ago
mysqli::query() can only execute one SQL statement.

Use mysqli::multi_query() when you want to run multiple SQL statements within one query.
up
-15
hunreal at gmail dot com
18 years ago
Use difference collation/character for connect, result.
You can set the collation before your query.

E.g. want to set the collation to utf8_general_ci
you can send the query "SET NAMES 'utf8'" first

<?php
$mysqli
=new mysqli('localhost', 'root', 'password', 'test');
$mysqli->query("SET NAMES 'utf8'");
$q=$mysqli->query("select * from test");
while(
$r=$q->fetch_assoc()) {
   
print_r($r);
}
?>

There are many variables about character settings.
By running sql command, SHOW VARIABLES LIKE 'char%';
There are some variables control the character usage.

character_set_client
character_set_connection
character_set_database
character_set_results
character_set_server
character_set_system

Also SET NAMES can repalce with one or some settings like SET character_set_results='utf8';
up
-16
marcus at synchromedia dot co dot uk
11 years ago
The exact type returned by a successful query is mysqli_result.
up
-19
ahmed dot 3abdolah at gmail dot com
8 years ago
Hi, i created function that add  a new table using array , i work with it on my projects ...
<?PHP
                  
/* this function was learned from PHP.net */
function array_keys_exist(&$key,array &$array){
               
$keys = split("\|",$key);
                foreach(
$keys as $key_s){
                    if(
array_key_exists($key_s, $array)) return true;
                    }
                return
false;
            }
/*and this is my function */
array_create_table(array &$array){
        if(
is_array($array)){
          
$key = "table|rows|values";   
       
$info = "";
        if(
array_keys_exist($key,$array)){
        if(
is_array($array["rows"]) and is_array($array["values"]) ){
                                        
            if(
count($array["rows"]) == count($array["values"])) {
                        for(
$i=0; $i<=count($array["rows"]); $i++){
   
$info = $info." ".$array["rows"][$i]." ".$array["values"][$i]." NOT NULL ";
            if(
$i < count($array["rows"])-1 ) $info = $info.",";
                    }
   
$query = "CREATE TABLE ".$this->private_tables_name.$array["table"]." ";
   
$query .= "( id INT NOT NULL AUTO_INCREMENT PRIMARY KEY, ".$info." )";
                    return
$query;   
                        }
                        }
                }else return
"Error";
                    }
            }

/* the use is simple */
$database = new database(); // connection to database i used mysqli ...
$array = array("table"=>"MRO", "rows"=>array("name","username") , "values" => array("VARCHAR (50) "," VARCHAR (50) ") );

$query = array_create_table($array); // convert and create the query ...
if($database->query($query)) echo "Work"; else echo "Error"; // result : work

?>
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-18
thomas dekker
12 years ago
Building inserts can be annoying. This helper function inserts an array into a table, using the key names as column names:

<?php
 
private function store_array (&$data, $table, $mysqli)
  {
   
$cols = implode(',', array_keys($data));
    foreach (
array_values($data) as $value)
    {
      isset(
$vals) ? $vals .= ',' : $vals = '';
     
$vals .= '\''.$this->mysql->real_escape_string($value).'\'';
    }
   
$mysqli->real_query('INSERT INTO '.$table.' ('.$cols.') VALUES ('.$vals.')');
  }
?>

Adapt it to your specific needs.
up
-19
popere dot noel at yahoo dot com
9 years ago
or you could just extend the class...
in my case i already had a wraper for the db so something like this was easy :

public function  free($result) {
 
  $result->free_result();
$this->link->next_result();
}

just tried it and it works like a charm ;-)
up
-10
omidbahrami1990 at gmail dot com
4 years ago
This Is A Secure Way To Use mysqli::query
--------------------------------------------------------
<?php
function secured_query($sql)
{
$connection = new mysqli($host,$username,$password,$name);
   
if (
$connection->connect_error)
die(
"Secured");
   
$result=$connection->query($sql);
if(
$result==FALSE)
die(
"Secured");
   
$connection->close();       
return
$result;   
}
/*
$host ---> DataBase IP Address
$username ---> DataBase Username
$password ---> DataBase Password
$name ---> DataBase Name
*/
?>
up
-23
blinki bill, argodak at yahoo dot com
9 years ago
Recently I had puzzling problem when performing DML queries, update in particular, each time a update query is called and then there are some more queries to follow this error will show on the page and go in the error_log:
"Fatal error:  Exception thrown without a stack frame in Unknown on line 0"

The strange thing is that all queries go through just fine so it didn't make much sense:

$update = mysqli_query($connection, $query_string);
if(!$update){
echo 'Houston we have a problem '.mysqli_error($connection);
exit;
}

In the above example "$update" is "true", mysqli_error() is empty and of course the update operation goes through, however the nasty super cryptic error appears on the page.
What makes even less sense to me is how I fixed it - just called "mysqli_free_result" after the update query and the problem was gone, however because mysqli_free_result is not supposed to be called after DML queries (to free what, a boolean? lol) it needs to be wrapped in a try catch block:

try{
mysqli_free_result($update);
}catch (Exception $e){
//do nothing
}

So, I don't know why but it seems that when DML queries are responsible for:
"Fatal error:  Exception thrown without a stack frame in Unknown on line 0"
calling "mysqli_free_result" after the query seems to be fixing the issue
up
-13
Anonymous
5 years ago
I don't know is it bug or something , then first I write it here . Query SHOW with MYSQLI_USE_RESULT option don't show num_rows :
<?php
SHOW TABLES LIKE
[some table], MYSQLI_USE_RESULT
num_rows
// shows 0 !
?>
up
-7
David Marcus
5 years ago
If you use the default resultmode of MYSQLI_STORE_RESULT, you can call $mysqli->close() right after $mysqli->query and before you use mysqli_result. This reduces the time the connection is open, which can help if the database server has a limit on how many connections there can be.
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