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mysql_fetch_assoc

(PHP 4 >= 4.0.3, PHP 5)

mysql_fetch_assoc連想配列として結果の行を取得する

警告

この拡張モジュールは PHP 5.5.0 で非推奨になり、PHP 7.0.0 で削除されました。 MySQLi あるいは PDO_MySQL を使うべきです。詳細な情報は MySQL: API の選択 を参照ください。 この関数の代替として、これらが使えます。

説明

mysql_fetch_assoc(resource $result): array

取得した行に対応する連想配列を返し、内部のデータポインタを前に進めます。 mysql_fetch_assoc() は、 mysql_fetch_array() の 2 番目のパラメータを MYSQL_ASSOC に指定してコールするのと同じ働きをします。つまり、 連想配列のみを返します。

パラメータ

result

評価された結果 リソース。この結果は、mysql_query() のコールにより得られたものです。

戻り値

取得した行に対応する文字列の連想配列を返します。行がもうない場合には false を返します。

結果の複数のカラムが同じフィールド名を有している場合、最後のカラ ムが優先されます。同じ名前を有する他のカラムにアクセスするには、 mysql_fetch_row()を使用して数値添字を返すか、 エイリアス名を追加する必要があります。エイリアスの説明については、 mysql_fetch_array()の例を参照ください。

例1 mysql_fetch_assoc() のいろいろな例

<?php

$conn
= mysql_connect("localhost", "mysql_user", "mysql_password");

if (!
$conn) {
echo
"Unable to connect to DB: " . mysql_error();
exit;
}

if (!
mysql_select_db("mydbname")) {
echo
"Unable to select mydbname: " . mysql_error();
exit;
}

$sql = "SELECT id as userid, fullname, userstatus
FROM sometable
WHERE userstatus = 1"
;

$result = mysql_query($sql);

if (!
$result) {
echo
"Could not successfully run query ($sql) from DB: " . mysql_error();
exit;
}

if (
mysql_num_rows($result) == 0) {
echo
"No rows found, nothing to print so am exiting";
exit;
}

// データ行が存在する間、それを $row に連想配列形式でセットする
// 注: 結果が 1 行であることがわかっているのなら、ループを利用しなくてもよい
// 注: ループ内で extract($row); を実行すれば、
// $userid, $fullname, そして $userstatus を利用できる
while ($row = mysql_fetch_assoc($result)) {
echo
$row["userid"];
echo
$row["fullname"];
echo
$row["userstatus"];
}

mysql_free_result($result);

?>

注意

注意: パフォーマンス

特筆すべき点として、mysql_fetch_assoc() が 著しい付加価値があるにもかかわらず、 mysql_fetch_row()より それほど遅くはないということが言えます。

注意: この関数により返されるフィー ルド名は 大文字小文字を区別 します。

注意: この関数は、 NULL フィールドに PHPの null 値を設定します。

参考

add a note

User Contributed Notes 6 notes

up
5
marREtijn dot posthMOuma at hoVEme dot nl
21 years ago
It appears that you can't have table.field names in the resulting array.
Just use an alias if your results come up empty and you are using multi-table query's:

$res=mysql_query("SELECT user.ID AS uID, order.ID AS oID FROM user, order WHERE ( order.userid=uID )";
while ($row=mysql_fetch_assoc($res)) {
echo "<p>userid: $row['uID'], orderid: $row['oID']</p>";
}
up
5
joe at kybert dot com
20 years ago
Worth pointing out that the internal row pointer is incremented once the data is collected for the current row.

This means that multiple calls will iterate through the row data, so you DONT need to mysql_data_seek(..) between calls.

This is noted in the mysql_fetch_row() docs, but not here!?
up
0
Typer85 at gmail dot com
17 years ago
Please be advised that the resource result that you pass to this function can be thought of as being passed by reference because a resource is simply a pointer to a memory location.

Because of this, you can not loop through a resource result twice in the same script before resetting the pointer back to the start position.

For example:

----------------
<?php

// Assume We Already Queried Our Database.

// Loop Through Result Set.

while( $queryContent = mysql_fetch_row( $queryResult ) {

// Display.

echo $queryContent[ 0 ];
}

// We looped through the resource result already so the
// the pointer is no longer pointing at any rows.

// If we decide to loop through the same resource result
// again, the function will always return false because it
// will assume there are no more rows.

// So the following code, if executed after the previous code
// segment will not work.

while( $queryContent = mysql_fetch_row( $queryResult ) {

// Display.

echo $queryContent[ 0 ];
}

// Because $queryContent is now equal to FALSE, the loop
// will not be entered.

?>
----------------

The only solution to this is to reset the pointer to make it point at the first row again before the second code segment, so now the complete code will look as follows:

----------------
<?php

// Assume We Already Queried Our Database.

// Loop Through Result Set.

while( $queryContent = mysql_fetch_row( $queryResult ) {

// Display.

echo $queryContent[ 0 ];
}

// Reset Our Pointer.

mysql_data_seek( $queryResult );

// Loop Again.

while( $queryContent = mysql_fetch_row( $queryResult ) {

// Display.

echo $queryContent[ 0 ];
}

?>
----------------

Of course you would have to do extra checks to make sure that the number of rows in the result is not 0 or else mysql_data_seek itself will return false and an error will be raised.

Also please note that this applies to all functions that fetch result sets, including mysql_fetch_row, mysql_fetch_assos, and mysql_fetch_array.
up
-3
george at georgefisher dot com
15 years ago
Thanks to to R. Bradley for the implode idea. The following fixes a few bugs and includes quote_smart functionality (and has been tested)

<?php
function mysql_insert_assoc ($my_table, $my_array) {

//
// Insert values into a MySQL database
// Includes quote_smart code to foil SQL Injection
//
// A call to this function of:
//
// $val1 = "foobar";
// $val2 = 495;
// mysql_insert_assoc("tablename", array(col1=>$val1, col2=>$val2, col3=>"val3", col4=>720, col5=>834.987));
//
// Sends the following query:
// INSERT INTO 'tablename' (col1, col2, col3, col4, col5) values ('foobar', 495, 'val3', 720, 834.987)
//

global $db_link;

// Find all the keys (column names) from the array $my_array
$columns = array_keys($my_array);

// Find all the values from the array $my_array
$values = array_values($my_array);

// quote_smart the values
$values_number = count($values);
for (
$i = 0; $i < $values_number; $i++)
{
$value = $values[$i];
if (
get_magic_quotes_gpc()) { $value = stripslashes($value); }
if (!
is_numeric($value)) { $value = "'" . mysql_real_escape_string($value, $db_link) . "'"; }
$values[$i] = $value;
}

// Compose the query
$sql = "INSERT INTO $my_table ";

// create comma-separated string of column names, enclosed in parentheses
$sql .= "(" . implode(", ", $columns) . ")";
$sql .= " values ";

// create comma-separated string of values, enclosed in parentheses
$sql .= "(" . implode(", ", $values) . ")";

$result = @mysql_query ($sql) OR die ("<br />\n<span style=\"color:red\">Query: $sql UNsuccessful :</span> " . mysql_error() . "\n<br />");

return (
$result) ? true : false;
}
?>
up
-4
R. Bradley
18 years ago
In response to Sergiu's function - implode() would make things a lot easier ... as below:

<?php
function mysql_insert_assoc ($my_table, $my_array) {

// Find all the keys (column names) from the array $my_array
$columns = array_keys($my_array);

// Find all the values from the array
$values = array_values($my_array);

// We compose the query
$sql = "insert into `$my_table` ";
// implode the column names, inserting "\", \"" between each (but not after the last one)
// we add the enclosing quotes at the same time
$sql .= "(\"" . implode("\", \"", $column_names) . "\")";
$sql .= " values ";
// Same with the values
$sql .= "(" . implode(", ", $values) . ")";

$result = mysql_query($sql);

if (
$result)
{
echo
"The row was added sucessfully";
return
true;
}
else
{
echo (
"The row was not added<br>The error was" . mysql_error());
return
false;
}
}
?>

Thus, a call to this function of:
mysql_insert_assoc("tablename", array("col1"=>"val1", "col2"=>"val2"));

Sends the following sql query to mysql:
INSERT INTO `tablename` ("col1", "col2") VALUES ("val1", "val2")
up
-5
benlanc at ster dot me dot uk
19 years ago
It probably without saying, but using list() in conjunction with mysql_fetch_assoc() does not work - use mysql_fetch_row() instead.

<?php
$sql
= "SELECT `id`,`field`,`value` FROM `table`";
$result = mysql_query($sql);

// this results in empty values for rowID,fieldName,myValue
list($rowID,$fieldName,$myValue) = mysql_fetch_assoc($result);

// this is what you want:
list($rowID,$fieldName,$myValue) = mysql_fetch_row($result);
?>
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