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strripos

(PHP 5, PHP 7, PHP 8)

strriposFind the position of the last occurrence of a case-insensitive substring in a string

Descrição

strripos(string $haystack, string $needle, int $offset = 0): int|false

Find the numeric position of the last occurrence of needle in the haystack string.

Unlike the strrpos(), strripos() is case-insensitive.

Parâmetros

haystack

The string to search in.

needle

The string to search for.

Antes do PHP 8.0.0, se needle não for uma string, ela será convertida para um número inteiro e aplicada como o valor ordinal de um caractere. Este comportamento tornou-se defasado a partir do PHP 7.3.0 e depender dele é altamente desaconselhado. Dependendo do comportamento pretendido, o parâmetro needle deve ser explicitamente convertido em string ou uma chamada explícita para chr() deve ser realizada.

offset

If zero or positive, the search is performed left to right skipping the first offset bytes of the haystack.

If negative, the search is performed right to left skipping the last offset bytes of the haystack and searching for the first occurrence of needle.

Nota:

This is effectively looking for the last occurrence of needle before the last offset bytes.

Valor Retornado

Returns the position where the needle exists relative to the beginnning of the haystack string (independent of search direction or offset).

Nota: String positions start at 0, and not 1.

Returns false if the needle was not found.

Aviso

Esta função pode retornar o valor booleano false, mas também pode retornar um valor não booleano que pode ser avaliado como false. Leia a seção sobre Booleanos para mais informações. Use o operador === para testar o valor retornado por esta função.

Registro de Alterações

Versão Descrição
8.2.0 A redução de todas as letras a maiúsculas ou minúsculas não depende mais da localidade definida com setlocale(). Somente a redução de todas as letras ASCII a maiúsculas ou minúsculas será feita. Os bytes não ASCII serão comparados por seu valor de byte.
8.0.0 O parâmetro needle agora aceita uma string vazia.
8.0.0 Passing an int as needle is no longer supported.
7.3.0 Passing an int as needle has been deprecated.

Exemplos

Exemplo #1 A simple strripos() example

<?php
$haystack
= 'ababcd';
$needle = 'aB';

$pos = strripos($haystack, $needle);

if (
$pos === false) {
echo
"Sorry, we did not find ($needle) in ($haystack)";
} else {
echo
"Congratulations!\n";
echo
"We found the last ($needle) in ($haystack) at position ($pos)";
}
?>

O exemplo acima produzirá:

Congratulations!
   We found the last (aB) in (ababcd) at position (2)

Veja Também

  • strpos() - Find the position of the first occurrence of a substring in a string
  • stripos() - Find the position of the first occurrence of a case-insensitive substring in a string
  • strrpos() - Find the position of the last occurrence of a substring in a string
  • strrchr() - Find the last occurrence of a character in a string
  • stristr() - Case-insensitive strstr
  • substr() - Retorna parte de uma string

add a note

User Contributed Notes 7 notes

up
4
Yanik Lupien
16 years ago
Simple way to implement this function in PHP 4

<?php
if (function_exists('strripos') == false) {
function
strripos($haystack, $needle) {
return
strlen($haystack) - strpos(strrev($haystack), $needle);
}
}

?>
up
2
dimmav at in dot gr
15 years ago
Suppose you just need a stripos function working backwards expecting that strripos does this job, you better use the following code of a custom function named strbipos:

<?php
function strbipos($haystack="", $needle="", $offset=0) {
// Search backwards in $haystack for $needle starting from $offset and return the position found or false

$len = strlen($haystack);
$pos = stripos(strrev($haystack), strrev($needle), $len - $offset - 1);
return ( (
$pos === false) ? false : $len - strlen($needle) - $pos );
}

// Test
$body = "01234Xy7890XYz456xy90";
$str = "xY";
$len = strlen($body);
echo
"TEST POSITIVE offset VALUES IN strbipos<br>";
for (
$i = 0; $i < $len; $i++) {
echo
"Search in [$body] for [$str] starting from offset [$i]: [" . strbipos($body, $str, $i) . "]<br>";
}
?>

Note that this function does exactly what it says and its results are different comparing to PHP 5 strripos function.
up
1
peev[dot]alexander at gmail dot com
16 years ago
I think you shouldn't underestimate the length of $needle in the search of THE FIRST POSITION of it's last occurrence in the string. I improved the posted function, with added support for offset. I think this is an exact copy of the real function:

<?php
if(!function_exists("strripos")){
function
strripos($haystack, $needle, $offset=0) {
if(
$offset<0){
$temp_cut = strrev( substr( $haystack, 0, abs($offset) ) );
}
else{
$temp_cut = strrev( substr( $haystack, $offset ) );
}
$pos = strlen($haystack) - (strpos($temp_cut, strrev($needle)) + $offset + strlen($needle));
if (
$pos == strlen($haystack)) { $pos = 0; }
return
$pos;
}
/* endfunction strripos*/
}/* endfunction exists strripos*/
?>
up
-1
Anonymous
13 years ago
Generally speaking, linear searches are from start to end, not end to start - which makes sense from a human perspective. If you need to find strings in a string backwards, reverse your haystack and needle rather than manually chopping it up.
up
-1
peev[dot]alexander at gmail dot com
15 years ago
OK, I guess this will be the final function implementation for PHP 4.x versions ( my previous posts are invalid )

<?php

if(!function_exists("stripos")){
function
stripos( $str, $needle, $offset = 0 ){
return
strpos( strtolower( $str ), strtolower( $needle ), $offset );
}
/* endfunction stripos */
}/* endfunction exists stripos */

if(!function_exists("strripos")){
function
strripos( $haystack, $needle, $offset = 0 ) {
if( !
is_string( $needle ) )$needle = chr( intval( $needle ) );
if(
$offset < 0 ){
$temp_cut = strrev( substr( $haystack, 0, abs($offset) ) );
}
else{
$temp_cut = strrev( substr( $haystack, 0, max( ( strlen($haystack) - $offset ), 0 ) ) );
}
if( (
$found = stripos( $temp_cut, strrev($needle) ) ) === FALSE )return FALSE;
$pos = ( strlen( $haystack ) - ( $found + $offset + strlen( $needle ) ) );
return
$pos;
}
/* endfunction strripos */
}/* endfunction exists strripos */
?>
up
-3
ElectroFox
16 years ago
Sorry, I made that last post a bit prematurely. One more thing wrong with the simple php4 version is that it breaks if the string is not found. It should actually look like this:

<?php
if (function_exists('strripos') == false) {
function
strripos($haystack, $needle) {
$pos = strlen($haystack) - strpos(strrev($haystack), strrev($needle));
if (
$pos == strlen($haystack)) { $pos = 0; }
return
$pos;
}
}
?>

Note, we now check to see if the $needle was found, and if it isn't, we return 0.
up
-7
admin at e-xxi dot net
13 years ago
strripos() has very strange behaviour when you provide search position. For some reason it searches forward from the given position, instead of searching backward, that is more logical.

For example if you want to find instanse of $what, previous to the last, strripos($where, $what, $last_what_pos-1) will not wark as expected. It will return $last_what_pos again and again. And that has no sence at all.

To prevent this, I just used $prev_last_what_pos = strripos(substr($where,0,$last_what_pos), $what);
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