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ltrim

(PHP 4, PHP 5, PHP 7, PHP 8)

ltrim文字列の最初から空白 (もしくはその他の文字) を取り除く

説明

ltrim(string $string, string $characters = " \n\r\t\v\x00"): string

文字列の最初から空白 (もしくはその他の文字) を取り除きます。

パラメータ

string

入力文字列。

characters

charactersパラメータにより、削除する 文字を指定することも可能です。削除したい全ての文字をリストに してください。..を文字の範囲を指定する際に 使用可能です。

戻り値

この関数は string の最初から空白文字を取り除き、 取り除かれた文字列を返します。2番目のパラメータを指定しない場合、 ltrim()は以下の文字を削除します。

  • " " (ASCII 32 (0x20)), 通常の空白。
  • "\t" (ASCII 9 (0x09)), タブ。
  • "\n" (ASCII 10 (0x0A)), 改行。
  • "\r" (ASCII 13 (0x0D)), 復帰。
  • "\0" (ASCII 0 (0x00)), NUL バイト。
  • "\v" (ASCII 11 (0x0B)), 垂直タブ。

例1 ltrim() の使用例

<?php

$text
= "\t\tThese are a few words :) ... ";
$binary = "\x09Example string\x0A";
$hello = "Hello World";
var_dump($text, $binary, $hello);

print
"\n";


$trimmed = ltrim($text);
var_dump($trimmed);

$trimmed = ltrim($text, " \t.");
var_dump($trimmed);

$trimmed = ltrim($hello, "Hdle");
var_dump($trimmed);

// ASCII 制御文字 (0 から 31 まで) を
// $binary の先頭から取り除きます
$clean = ltrim($binary, "\x00..\x1F");
var_dump($clean);

?>

上の例の出力は以下となります。

string(32) "        These are a few words :) ...  "
string(16) "    Example string
"
string(11) "Hello World"

string(30) "These are a few words :) ...  "
string(30) "These are a few words :) ...  "
string(7) "o World"
string(15) "Example string
"

参考

  • trim() - 文字列の先頭および末尾にあるホワイトスペースを取り除く
  • rtrim() - 文字列の最後から空白 (もしくはその他の文字) を取り除く

add a note

User Contributed Notes 8 notes

up
84
tavi undersc 10 from yahoocom
8 years ago
When using a $character_mask the trimming stops at the first character that is not on that mask.

So in the $string = "Hello world" example with $character_mask = "Hdle", ltrim($hello, $character_mask) goes like this:
1. Check H from "Hello world" => it is in the $character_mask, so remove it
2. Check e from "ello world" => it is in the $character_mask, so remove it
3. Check l from "llo world" => it is in the $character_mask, so remove it
4. Check l from "lo world" => it is in the $character_mask, so remove it
5. Check o from "o world" => it is NOT in the $character_mask, exit the function

Remaining string is "o world".

I hope it helps someone as I had a confusing moment with this function.
up
21
Usamah M dot Ali (usamah1228 at gmail dot com)
16 years ago
For those who use right-to-left languages such as Arabic, Hebrew, etc., it's worth mentioning that ltrim() (which stands for left trim) & rtrim() (which stands for right trim) DO NOT work contextually. The nomenclature is rather semantically incorrect. So in an RTL script, ltrim() will trim text from the right direction (i.e. beginning of RTL strings), and rtrim() will trim text from the left direction (i.e. end of RTL strings).
up
6
dzek dot remove_this at dzek dot eu
12 years ago
Guys, if += 0 is producing wrong values sometimes, and preg_replace is cpu consuming, then just stick to the main function described on that page, and use:
<?php
$value
= ltrim($value, '0');
?>
should be the fastest and most reliable.
I think all those comments can be misleading for begginers checking this page - it's sort of using magic tricks to reinvent the wheel.
up
-6
mroeling at exed dot nl
9 years ago
@scion4581

The problem is that the character mask (_stw in your case) isn't a literal string, but a character collection. So all characters within _stw are stripped. In your case this includes the w of weight also.
up
-6
Mauro
6 years ago
I noticed one thing.

Suppose you have to ltrim zeroes from strings like "015", "002", etc. and convert them back to numbers, eg. using intval.

Suppose you must convert to number "000" too.

In this case:

$trimmedString = ltrim('000', '0');

the value of $trimmedString would be NULL (and I think the docs should mention this).

Anyway, I initially thought I had to conditional check for this '000', but I found that intval(NULL) returns 0 (this thing is not in the docs of intval but is in a comment)
up
-22
John Sherwood
17 years ago
To remove leading/trailing zeroes (example: "0123.4560"), doing a += 0 is easier than trim tricks.
up
-15
juan at ecogomera dot com
10 years ago
+=0 not valid for something like 0000-5. Result is 0
up
-30
Mike
13 years ago
Keep in mind the amount of resources preg_replace() uses.
I would suggest a simple if statement if you need to parse through large amounts of data.
<?php
function remove_leading_zeros_from_number($number_string) {
$limit = 9000.1
$temp
= $number
(float) $temp;
if (
$number < $limit) {
$number += 0;
} else {
preg_replace('~^[0]*([1-9][0-9]*)$~','$1',$number_string)
}
}
?>

Code is untested, but probably sound.
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