intdiv

(PHP 7)

intdivInteger division

Description

intdiv ( int \$dividend , int \$divisor ) : int

Returns the integer quotient of the division of dividend by divisor.

Parameters

dividend

Number to be divided.

divisor

Number which divides the dividend.

Return Values

The integer quotient of the division of dividend by divisor.

Errors/Exceptions

If divisor is 0, a DivisionByZeroError exception is thrown. If the dividend is PHP_INT_MIN and the divisor is -1, then an ArithmeticError exception is thrown.

Examples

Example #1 intdiv() example

<?php
var_dump
(intdiv(32));
var_dump(intdiv(-32));
var_dump(intdiv(3, -2));
var_dump(intdiv(-3, -2));
var_dump(intdiv(PHP_INT_MAXPHP_INT_MAX));
var_dump(intdiv(PHP_INT_MINPHP_INT_MIN));
var_dump(intdiv(PHP_INT_MIN, -1));
var_dump(intdiv(10));
?>
int(1)
int(-1)
int(-1)
int(1)
int(1)
int(1)

Fatal error: Uncaught ArithmeticError: Division of PHP_INT_MIN by -1 is not an integer in %s on line 8
Fatal error: Uncaught DivisionByZeroError: Division by zero in %s on line 9

• / - Floating-point division
• % - Integer modulus
• fmod() - Floating-point modulo

35
AmeenRoss
4 years ago
This does indeed seem to be equal to intdiv:

<?php
function intdiv_1(\$a, \$b){
return (
\$a - \$a % \$b) / \$b;
}
?>

However, this isn't:

<?php
function intdiv_2(\$a, \$b){
return
floor(\$a / \$b);
}
?>

Consider an example where either of the parameters is negative:
<?php
\$param1
= -10;
\$param2 = 3;
print_r([

'modulus' => intdiv_1(\$param1, \$param2),

'floor' => intdiv_2(\$param1, \$param2),
]);

/**
* Array
* (
*     [modulus] => -3
*     [floor] => -4
* )
*/
?>
-13
polettog at gmail dot com
4 years ago
Without intdiv(), the following may be a good way (with \$a and \$b of type integer and not too big) :
<?php
(int)(\$a / \$b)
?>
because in case of divisible integers, the result will be integer and there is no risk of float appearing round but below their represented value (like the case (0.1+0.7)*10).
\$a and \$b really needs to be of type integer though.
If they are too big and indivisible, some precision will be lost during the conversion to float and the result may be inaccurate.
-20
Ts.Saltan
4 years ago
\$a = 57;
\$b = 3;

var_dump(
intdiv(\$a,\$b),
intdiv_1(\$a,\$b),
intdiv_2(\$a,\$b)
);

function intdiv_1(\$a, \$b){
return (\$a-\$a%\$b)/\$b;
}

function intdiv_2(\$a, \$b){
return floor(\$a/\$b);
}
//intdiv(\$a, \$b) == floor(\$a/\$b) == (\$a-\$a%\$b)/\$b
-25
Bubonic dot pestilence at gmail dot com
3 years ago
<?php

function intdiv_2(\$a, \$b)  {

\$val = \$a / \$b;
return (
\$val < 0 ? "ceil" : "floor") (\$val);
}

?>

Aren't this?! 